With the previous determined multiplier, place them as coefficients in front of oxidizing and reducing species to balance the oxidized and reduced atoms within. In this case, the coefficients of Cr2O72-, HNO2, Cr3+ and NO3- in the equation are determined by the bracket information, which indicates that two Cr atoms undergo an oxidation change for every three N atoms that change. Therefore, place 2 (1x2) in front of Cr3+ and place 3 in front of both HNO2 and NO3-.
In a disproportionation reaction, the coefficients of the substance involved in oxidation and reduction can be combined into one. In the case below, 3 (2+1) for HNO2 (one of them undergoes oxidation and two of them undergo reduction), 1 for HNO3 and 2 for NO.